From: "Alexey Malistov" <CyrTeX-ru@vsu.ru>
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Date: Mon, 17 Jan 2011 19:38:01 +0300
Reply-To: Alexey Malistov <Alexey.Malistov@biones.com>
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$$
\sigma(\theta)=3D-\frac{\sum\limits_{k=3D0}^q\alpha_k e^{i
(q-k)\theta}} {\beta_0 e^{i q\theta}},
$$


=FA=C4=D2=C1=D7=D3=D4=D7=D5=CA=D4=C5, Mihail.

=F7=D9 =D0=C9=D3=C1=CC=C9 17 =D1=CE=D7=C1=D2=D1 2011 =C7., 19:22:43:

> =F5=D7=C1=D6=C1=C5=CD=D9=C5 =F4=C5=C8=CE=C9=CB=C9!

> =D7=C5=D2=D3=D4=CB=C1 =C4=CC=D1 =D4=C5=CB=D3=D4=C1 (=CF=C4=CE=C1 =CB=CF=
=CC=CF=CE=CB=C1)
> \begin{equation}\label{eq6}
> \sigma(\theta)=3D-\frac{- e^{i q\theta} + \alpha_1 e^{i
> (q-1)\theta}+\alpha_2 e^{i (q-2)\theta}+\ldots+\alpha_{q-1} e^{i
> \theta}+\alpha_q} {\beta_0 e^{i q\theta}},
> \end{equation}

> =D7=C5=D2=D3=D4=CB=C1 =C4=CC=D1 =D4=C5=CB=D3=D4=C1 (=C4=D7=C5 =CB=CF=CC=
=CF=CE=CB=C9)
> \begin{equation}\label{eq6}
> \sigma(\theta)=3D-\frac{\binom{- e^{i q\theta} + \alpha_1 e^{i
> (q-1)\theta}+\alpha_2 e^{i (q-2)\theta}+}{+\ldots+\alpha_{q-1}
> e^{i \theta}+\alpha_q}}{\beta_0 e^{i q\theta}},
> \end{equation}

> =EB=C1=CB =C5=DD=C5 =CD=CF=D6=CE=CF =D0=D2=CF=D7=C5=D3=D4=C9 =D7=C5=D2=D3=
=D4=CB=D5 =C4=CC=D1 =C4=D7=D5=C8 =CB=CF=CC=CF=CE=CF=CB, =CE=CF =D4=C1=CB =
=DE=D4=CF=C2=D9 =D2=C1=DA=CD=C5=D2 =D4=C5=CB=D3=D4=C1 =CE=C5 =D5=CD=C5=CE=
=D8=DB=C1=CC=D3=D1?
> =E9=D3=D0=CF=CC=D8=DA=CF=D7=C1=D4=D8 =CD=C1=D4=D2=C9=C3=D9 (=D7=C5=CB=D4=
=CF=D2-=D3=D4=CF=CC=C2=C3=D9)?
> --
> =F3 =D5=D7=C1=D6=C5=CE=C9=C5=CD
> =F3=C5=CD=C5=CE=CF=D7 =ED=C9=C8=C1=C9=CC
> -


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=F3 =D5=D7=C1=D6=C5=CE=C9=C5=CD,
 =E1=CC=C5=CB=D3=C5=CA =ED=C1=CC=C9=D3=D4=CF=D7                         =20=